Question
Quantitative Aptitude Question on Algebra
A shop wants to sell a certain quantity (in kg) of grains. It sells half the quantity and an additional 3 kg of these grains to the first customer. Then, it sells half of the remaining quantity and an additional 3 kg of these grains to the second customer. Finally, when the shop sells half of the remaining quantity and an additional 3 kg of these grains to the third customer, there are no grains left. The initial quantity, in kg, of grains is
42
18
36
50
42
Solution
Let the initial quantity of grains be x. The first customer buys half of x plus 3 kg, leaving 2x−3 kg. The second customer then buys half of the remaining grains plus 3 kg, leaving 4x−3 kg. The third customer buys half of what is left plus 3 kg, leaving 0 grains. Thus, we have the equation:
8x−3=0⟹x=42