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Question

Quantitative Aptitude Question on Mixture Problems

A shop owner bought a total of 64 shirts from a wholesale market that came in two sizes, small and large. The price of a small shirt was INR 50 less than that of a large shirt.She paid a total of INR 5000 for the large shirts, and a total of INR 1800 for the small shirts.Then, the price of a large shirt and a small shirt together, in INR, is

A

150

B

225

C

175

D

200

Answer

200

Explanation

Solution

Let number of small shirts be xx and price of a small shirt be yy.
Then number of large shirts be (64x)(64 - x) and the price of a large shirt becomes (y+50)(y + 50)
Total Money spent on small shirts,
xy=1800xy = 1800
Total money spent on large shirts,
(64x)(y+50)=5000(64 - x) (y + 50) = 5000
(64x)(y+50)=5000(64 - x) (y + 50) = 5000
64y+3200xy50x=500064y + 3200 - xy - 50x = 5000
64y+3200180050x=500064y + 3200 - 1800 - 50x = 5000
64y+140050x=500064y + 1400 - 50x = 5000
64y50x=360064y - 50x = 3600
32y25x=180032y - 25x = 1800
32y - 25$$($$\frac{1800}{y}) =1800= 1800
32y21800y25(1800)=032y^2 - 1800y - 25(1800) = 0
4y29(25)y25(9)(25)=04y^2 - 9(25)y - 25(9)(25) = 0
y=75y = 75
Price of a small shirt =y=75= y= 75
Price of a small shirt =y+50=125= y + 50 = 125
The Total price of a large shirt and a small shirt,
=75+125= 75 + 125
=200= 200

So, the correct option is (D): 200200