Question
Quantitative Aptitude Question on Mixture Problems
A shop owner bought a total of 64 shirts from a wholesale market that came in two sizes, small and large. The price of a small shirt was INR 50 less than that of a large shirt.She paid a total of INR 5000 for the large shirts, and a total of INR 1800 for the small shirts.Then, the price of a large shirt and a small shirt together, in INR, is
150
225
175
200
200
Solution
Let number of small shirts be x and price of a small shirt be y.
Then number of large shirts be (64−x) and the price of a large shirt becomes (y+50)
Total Money spent on small shirts,
xy=1800
Total money spent on large shirts,
(64−x)(y+50)=5000
(64−x)(y+50)=5000
64y+3200−xy−50x=5000
64y+3200−1800−50x=5000
64y+1400−50x=5000
64y−50x=3600
32y−25x=1800
32y - 25$$($$\frac{1800}{y}) =1800
32y2−1800y−25(1800)=0
4y2−9(25)y−25(9)(25)=0
y=75
Price of a small shirt =y=75
Price of a small shirt =y+50=125
The Total price of a large shirt and a small shirt,
=75+125
=200
So, the correct option is (D): 200