A S.H.M. has amplitude ‘a’ and time period T. The maximum ve... | PHYSICS - VELOCITY AND ACCELERATION IN SIMPLE HARMONIC MOTION | SolveeIt | Solveeit

Today, August 19

Question

A S.H.M. has amplitude ‘a’ and time period T. The maximum velocity will be

A

$\frac{4a}{T}$

B

$\frac{2a}{T}$

C

$2\pi\sqrt{\frac{a}{T}}$

D

$\frac{2\pi a}{T}$

Answer

$\frac{2\pi a}{T}$

Explanation

Solution

$A = - a\omega^{2}\omega t = a\omega^{2}\sin(\omega t + \pi)$