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Question

Physics Question on laws of motion

A ship of mass 3×1073\times 10^7 kg initially at rest, is pulled by a force of 5×104N5\times 10^4 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is

A

1.5 m/s

B

60 m/s

C

0.1m/s

D

5 m/s

Answer

0.1m/s

Explanation

Solution

a=Fm=5×1043×107=53×103m/s2a=\frac{F}{m}=\frac{5\times 10^4}{3\times10^7}=\frac{5}{3}\times10^{-3} m/s^2
\hspace25mm v=\sqrt{2as}
\hspace25mm =\sqrt{2\times\frac{5}{3}\times10^{-3}\times3}
= 0.1 m/s