Question
Physics Question on laws of motion
A ship of mass 3×107 kg initially at rest, is pulled by a force of 5×104N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is
A
1.5 m/s
B
60 m/s
C
0.1m/s
D
5 m/s
Answer
0.1m/s
Explanation
Solution
a=mF=3×1075×104=35×10−3m/s2
\hspace25mm v=\sqrt{2as}
\hspace25mm =\sqrt{2\times\frac{5}{3}\times10^{-3}\times3}
= 0.1 m/s