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Question

Physics Question on Motion in a plane

A shell fired from a gun at sea level rises to a maximum height of 5km5\, km when fired at a ship 20km20 \,km away. The muzzle velocity should be

A

7m/s7 \,m/s

B

14m/s14 \,m/s

C

28m/s28 \,m/s

D

56m/s56 \,m/s

Answer

56m/s56 \,m/s

Explanation

Solution

H=5000m=uy22gH = 5000\,m = \frac{u_y^2}{2g}
=uy22×10= \frac{u_y^2}{2\times 10}
uy2=100000u_y^2 = 100000
or uy=10010ms...(i)u_y = 100 \sqrt{10} \frac{m}{s}\,\,\,...(i)
R=20,000m=2uxuygR = 20, 000\,m = \frac{2u_x \,u_y}{g}
=2×ux10×10010= \frac{2\times u_x}{10} \times 100\sqrt{10}
or ux=10010...(ii)u_x = 100\sqrt{10}\,\,\,...(ii)
Now, u=ux2+uy2u = \sqrt{u_x^2 + u_y^2}
=10020m/s= 100\sqrt{20}\,m/s