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Question

Mathematics Question on Sets

A set A has 3 elements and another set B has 6 elements. Then

A

3≤n(A∪B)≤63 \le n (A \cup B) \le 6

B

3≤n(A∪B)≤93 \le n (A \cup B) \le 9

C

6≤n(A∪B)≤96 \le n (A \cup B) \le 9

D

0≤n(A∪B)≤90 \le n (A \cup B) \le 9

Answer

6≤n(A∪B)≤96 \le n (A \cup B) \le 9

Explanation

Solution

We have min n (A ∪\cup B) = max {n(A), n (B)} = max {3, 6} = 6 Max n (A ∪\cup B) = n (A) + n (B) = 9 ∴ 6≤n(A∪B)≤9\therefore \, 6 \le n (A \cup B) \le 9