Question

A sealed tube which can withstand a pressure of 3 atmosphere is filled with air at $27^{o}C$ and 760 mm pressure. The temperature above which the tube will burst will be

• A. $900^{o}C$
• B. $627^{o}C$
• C. $627^{o}C$
• D. $1173^{o}C$

Answer 1

Answer: (B)

$627^{o}C$

Answer 2

The tube will burst when the final pressure exceeds 3 atm. at constant volume,

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$ i.e. $\frac{760}{300K} = \frac{3 \times 760}{T_{2}}$

$T_{2} = 900K = 627^{o}C$