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Question

Physics Question on kinetic theory

A sealed container with negligible coefficient of volumetric expansion contains helium (a monoatomic gas). When it is heated from 300 K to 600 K, the average KE of helium atoms is

A

halved

B

unchanged

C

doubled

D

increased by factor 2 \sqrt 2

Answer

doubled

Explanation

Solution

K=12mvms2K =\frac{1}{2} mv _{ ms }^{2}
vrms=3KTMv _{ rms }=\sqrt{\frac{3 KT }{ M }}
vrmsTv _{ rms } \propto \sqrt{ T }
K2K1=(T2T1)2\frac{ K _{2}}{ K _{1}}=\left(\sqrt{\frac{ T _{2}}{ T _{1}}}\right)^{2}
K2=K1T2T1K _{2}= K _{1} \frac{ T _{2}}{ T _{1}}
K2=K1600300K _{2}= K _{1} \frac{600}{300}
K2=2K1\Rightarrow K _{2}=2 K _{1}