Question

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

• A. 0.01 mm
• B. 0.25 mm
• C. 0.5 mm
• D. 1.0 mm

Answer 1

Answer: (C)

0.5 mm

Answer 2

L.C. $=\frac{\text{Pitch}}{\text{Number of division on circular scale}}$

$\Rightarrow 0.01\,mm=\frac{\text{pitch}}{50}$
$\Rightarrow$ pitch $=0.5\,mm$