Question
Question: A screw gauge has a least count of 0.001 cm. The number of devisions through which zero mark of circ...
A screw gauge has a least count of 0.001 cm. The number of devisions through which zero mark of circular scale has crossed the refrence line is 2. The zero error is –
A
–0.02 mm
B
–0.005 cm
C
- 0.02
D
- 0.02 cm
Answer
–0.02 mm
Explanation
Solution
Least count = 0.001 cm
Zero Error = – (2 × 0.001)
= – 0.002 cm = –0.02 mm