Solveeit Logo

Question

Question: A scooter company gives the following specifications about its product. -Weight of scooter \(95\,k...

A scooter company gives the following specifications about its product.
-Weight of scooter 95kg95\,kg.
-Maximum Speed 60kmhr160\,kmh{r^{ - 1}}.
-Maximum engine power 3.5hp3.5\,hp.
-Pick up time to get maximum speed 5s5\,s.
Check the validity of these specifications.

Explanation

Solution

In order to solve this question we need to understand what power of any device is. Power of a device is defined as a scalar product of force and velocity. It physically depicts how much energy any device can generate in a second. The more the energy is, the more efficient a device is. Also maximum speed means the largest distance a body covers in minimum time.

Complete step by step answer:
First we have to convert given values into SI units of each system.We know 1km=1000m1\,km = 1000\,m and 1hr=3600sec1hr = 3600\,\sec .So Maximum speed of vehicle in SI unit is 60×10003600msec160 \times \dfrac{{1000}}{{3600}}\,m\,{\sec ^{ - 1}} which is 16.67msec116.67\,m\,{\sec ^{ - 1}}.So the maximum speed of a vehicle is 16.67msec116.67\,m\,{\sec ^{ - 1}}.
So the maximum energy it can generate is given by,
E=12mv2E = \dfrac{1}{2}m{v^2}
Where “m” is mass of body and “v” is speed.
Since m=95kgm = 95kg given in question and v=16.67msec1v = 16.67\,m\,{\sec ^{ - 1}}

So putting values we get
E=12(95×16.67×16.67)E = \dfrac{1}{2}(95 \times 16.67 \times 16.67)
E=13194.45JE = 13194.45J
So the power of engine it can generate is P=EtP = \dfrac{E}{t}
Where “E” is energy and “t” is time.
t=5sec1t = 5{\sec ^{ - 1}}
Given in question and E=13194.15JE = 13194.15J
Putting values we get
P=13194.455Jsec1P = \dfrac{{13194.45}}{5}\,J{\sec ^{ - 1}}
P=2638.89Jsec1\Rightarrow P = 2638.89\,J{\sec ^{ - 1}}
Using conversion of 1Jsec1=0.0013hp1J{\sec ^{ - 1}} = 0.0013\,hp
P=(2638.89×0.0013)hpP = (2638.89 \times 0.0013)hp
P=3.43hp\therefore P = 3.43\,hp

Hence, given Specification is correct to near value and there is not much error.

Note: It should be remembered that horse power is the standard unit for denoting power of a vehicle. The more efficient the vehicle is, the more the engine horsepower. Also weight of any device is defined as a product of matter mass and acceleration due to gravity.Also Power is defined as Energy per unit time and product of force into velocity.