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Question

Physics Question on Gravitation

A saturn year is 29.529.5 times the earth year. How far is the saturn from the sun if the earth is 1.5×108km1.5 \times 10^8\, km away from the sun?

A

1.4×106km1.4 \times 10^6\, km

B

1.4×107km1.4 \times 10^7\, km

C

1.4×108km1.4 \times 10^8\, km

D

1.4×109km1.4 \times 10^9\, km

Answer

1.4×109km1.4 \times 10^9\, km

Explanation

Solution

Here, TS=29.5TET_S = 29.5T_E, RE=1.5×108kmR_E= 1.5 \times 10^8\, km, RS=?R_S = ? According to Keplers third law, T2R3T^{2} \propto R^{3} TS2TE2=RS3RE3\therefore \frac{T^{2}_{S}}{T^{2}_{E}} = \frac{R^{3}_{S}}{R^{3}_{E}}; RS=RE(TSTE)2/3R_{S} = R_{E} \left(\frac{T_{S}}{T_{E}}\right)^{2/3} RS=1.5×108(29.5TETE)2/3R_{S} = 1.5 \times 10^{8}\left(\frac{29.5T_{E}}{T_{E}}\right)^{2/3} =1.4×109km= 1.4 \times 10^{9}\,km