Question
Question: A satellite which is revolving around the earth has a minimum distance from earth equal to \[{r_1}\]...
A satellite which is revolving around the earth has a minimum distance from earth equal to r1 and maximum distance of r2, then the time period of the satellite will be?
Solution
Follow Kelper’s law of Periods where T2 is proportional to a3 .
Here, “a” refers to the semi-major axis.
Formula Used:
1. T2 is proportional to a3
\Rightarrow $$$${T^2} = \dfrac{{2\pi {a^3}}}{{GM}}
Where,
T= Time period of the satellite
a= semi-major axis
G= gravitational constant
M= mass of the earth (in this case)
Here, GM2π is the constant of proportionality
2. a=2r1+r2
Where,
r1 = Minimum distance covered
r2 = Maximum distance covered
Complete step by step answer:
Kepler’s gave three laws that describe the movement of planets around the sun .
Among this, the third law of Kepler, also known as the Law of periods states that:
The square of time period of revolution of the planet is proportional to the cube of semi major axis of the ellipse traced by the planet.
The above law can be formulated as follows:
T2 is proportional to a3
This equation is modified to :
T2=GM2πa3 - (i)
Where,
T= Time period of the satellite
A= semi-major axis
G= gravitational constant
M= mass of the earth (in this case)
Here, GM2π is the constant of proportionality.
So: T=GM2πa23
Now, we know the semi-major axis of an elliptical path is the arithmetic mean of the minimum and the maximum distance covered by the planet.
Therefore, in this case:
r1 = Minimum distance covered
r2 = Maximum distance covered
So,
a=2r1+r2
Putting the value of a equation (i) modifies to:
T=GM2π2(r1+r2)23
Thus, this is the value of the time period of the satellite.
Note: The semi-major axis of an elliptical path is the arithmetic mean of the minimum and the maximum distance covered by the planet.
The semi-minor axis is the geometric mean of minimum and the maximum distance covered by the planet, these two must not be confused.