Question

A satellite which is geostationary in a particular orbits is taken to another orbit, the distance of which is twice that of earlier orbit. The time period of the satellite in the second orbit is :

• A. 24 hrs.
• B. 48 hrs
• C. 48$\sqrt{2}$hrs
• D. $\frac{48}{\sqrt{2}}$ hrs.

Answer 1

Answer: (C)

48$\sqrt{2}$hrs

Answer 2

T² µ r³

$\frac{T_{1}}{T_{2}} = \left( \frac{r_{1}}{r_{2}} \right)^{3/2}$; $\frac{24hr}{T} = \left( \frac{r}{2r} \right)^{3/2}$

T = 24$(2\sqrt{2})$ ; T = $48\sqrt{2}$