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Question

Physics Question on Gravitation

A satellite moves in elliptical orbit about a planet. Its maximum and minimum velocities of satellites are 3×104m/s3\times 10^4 \, m/s and 1×103m/s1 \times 10^3 \, m/s respectively. What is the minimum distance of satellite from planet is maximum distance if 4×104km4 \times 10^4\, km

A

4×103km4 \times 10^3\, km

B

3×103km3 \times 10^3\, km

C

4/3×103km4/3 \times 10^3 \,km

D

1×103km1 \times 10^3\,km

Answer

4/3×103km4/3 \times 10^3 \,km

Explanation

Solution

If no external torque acts on a system, then angular momentum of the system does not change.
ie, If τ=0\tau=0
dLdt=0\Rightarrow \frac{d L}{d t} =0
L=\therefore L= constant
Hence,
mvmaxrmin=mvminrmaxm v_{\max } r_{\min } =m v_{\min } r_{\max }
rmin=vmin×rmaxvmax\Rightarrow r_{\min } =\frac{v_{\min } \times r_{\max }}{v_{\max }}
=1×103×4×1043×104=\frac{1 \times 10^{3} \times 4 \times 10^{4}}{3 \times 10^{4}}
=43×103km=\frac{4}{3} \times 10^{3}\, km