Question

A satellite is revolving around the earth in a circular orbit of radius $4$ times that of the parking orbit. The time period of the satellite is :

• A. 16 day
• B. 2 day
• C. 4 day
• D. 8 day

Answer 1

Answer: (D)

8 day

Answer 2

Applying Keplers law $T \propto r^{3 / 2}$ We know that time period of parking orbit is 1 day (given: $T_{s}=r$ parking orbit) Hence, $\frac{T_{s}}{T_{\text {parking }}}=\left(\frac{4 r_{\text {parking ortit }}}{r_{\text {parkhing orbit }}}\right)^{3 / 2}$ $=(4)^{3 / 2}=8$ $T_{s}=8 \times T_{\text {parking }}$ $=8 \times 1=8$ days