Solveeit Logo

Question

Physics Question on Gravitation

A satellite in force free space sweeps stationary interplanetary dust at a rate of dM/dt=αvdM/dt = \alpha v , where M is mass and v is the speed of satellite and α\alpha is a constant. The acceleration of satellite is

A

αv22M \frac{- \alpha v^2}{2M}

B

αv2- \alpha v^2

C

2αv2M \frac{- 2\alpha v^2}{M}

D

αv2M \frac{- \alpha v^2}{M}

Answer

αv2M \frac{- \alpha v^2}{M}

Explanation

Solution

Rate of change of mass dMdt=αv\frac{dM}{dt} = \alpha v.
Retarding force = Rate of change of momentum
= Velocity x Rate of change in mass = v×dMdt -v \times \frac{dM}{dt}
=v×αv=αv2.= - v \times \alpha v = - \alpha v^2 . (Minus sign of v due to deceleration)
Therefore Acceleration =αv2M= \frac{-\alpha v^2}{ M}.