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Question: A sample of \(NaN{O_3}\) weighing \(0.38g\) is placed in a \(50.0mL\) volumetric flask. The flask is...

A sample of NaNO3NaN{O_3} weighing 0.38g0.38g is placed in a 50.0mL50.0mL volumetric flask. The flask is then filled with water to the mark on the neck. What is the molarity of the solution?

Explanation

Solution

This question gives the knowledge about determining the molarity of the solution. Molarity is the ratio of number of moles of solute to the volume of the solution in litres. Molarity is the unit of concentration.
Formula used: The formula used to determine the number of moles is as follows:
n=wmn = \dfrac{w}{m}
Where ww is the given weight, nn is the number of moles of solute and mm is the molecular weight.
The formula used to determine the molarity of the solution is as follows:
M=nVM = \dfrac{n}{V}
Where MM is the molarity of the solution, nn is the number of moles of solute and VV is the volume of the solution in litres.

Complete step by step answer:
Molarity is the ratio of number of moles of solute to the volume of the solution in litres. Molarity is the unit of concentration. The SI unit of molarity is mol/Lmol/L and molarity is generally abbreviated as MM. Molarity is also termed as molar concentration. Molarity is very helpful in determining the concentration as well as dilution problems.
Now, we will determine the molarity of the solution by using the molarity formula as follows:
M=nV\Rightarrow M = \dfrac{n}{V}
To determine the molarity first we will require the number of moles of solute. The formula used to determine the number of moles is as follows:
n=wm\Rightarrow n = \dfrac{w}{m}
Substitute given weight as 0.38g0.38g and molecular weight of NaNO3NaN{O_3} as 8585 in the above formula.
n=0.3885\Rightarrow n = \dfrac{{0.38}}{{85}}
Now, to determine the molarity of the solution substitute nn as 0.3885\dfrac{{0.38}}{{85}}, volume in litres as 501000\dfrac{{50}}{{1000}} in the molarity formula.
M=0.3885×100050\Rightarrow M = \dfrac{{0.38}}{{85}} \times \dfrac{{1000}}{{50}}
On simplifying, we get
M=8.94×102\Rightarrow M = 8.94 \times {10^{ - 2}}

Therefore, the molarity of the solution is 8.94×102moles/L8.94 \times {10^{ - 2}}moles/L.

Note:
Always remember that the molarity is the ratio of number of moles of solute to the volume of the solution in litres. Molarity is used to determine the concentration of the solution. The SI unit of molarity is mol/Lmol/L and molarity is generally abbreviated as MM.