Question

A sample of ideal monoatomic gas is taken around the cycle ABC A as shown in figure. The work done during cycle is

• A. 9 PV
• B. 6 PV
• C. 3 PV
• D. zero

Answer 1

Answer: (C)

3 PV

Answer 2

Work done in a process is equal to $\int pdV =$ the area under the $p - V$ curve. Thus for the cyclic process shown, the area of the triangle enclosed is the work done in one complete cycle.
Thus $W =\frac{1}{2} \times 2 V \times 3 p =3 pV$