Question

A sample of H2SO4 is labeled as 86% by weight by weight. What is the molarity of acid?

Whet volume of acid to be used to make 1 litre of 0.2M H2SO4?

Answer 1

Molarity = n/v
Where, n= moles of solute
v= liter of solution

Moles of the solute= wt. of H₂SO₄ in1 L of solution/ mol wt. of H₂SO₄
Wt. of H₂SO₄ = strength x density x 1000
= 86/100 x1.787x 1000
= 1536.82

The molecular weight of H₂SO₄ is 98

Substituting the values, molarity = 1536.82/98 = 15.68 M

b) The molarity equation = M1V1= M2V2
In the question, M1= 15.68
M2= 0.2
V2= 1000

Substituting these values, 15.58 x V1= 0.2 X 1000
V1 = 200/15.68
= 12.75 mL