Solveeit Logo

Question

Question: A sample \(^{131}{I_{53}}\), as iodine ion, was administered to a patient in a carrier consisting of...

A sample 131I53^{131}{I_{53}}, as iodine ion, was administered to a patient in a carrier consisting of 0.10 mg0.10{\text{ }}mg of stable iodide ions. After 44 days, 66.67%66.67\% of the initial radioactivity was detected in the thyroid gland of the patient. What mass of the stable iodide ion had migrated to the thyroid gland? (t1/2=8days{t_{1/2}} = 8\,days)
A) 0.0958mg0.0958\,mg
B) 0.958mg0.958\,mg
C) 9.58mg9.58\,mg
D) None of these

Explanation

Solution

Activity in a radioactive reaction is the decay of unstable nuclei per second or it can be referred to as the rate of decay for that radioactive reaction.
-As we know the radioactive decay is a type of first order reaction this question can be solved by using the same formula and method used to calculate the activity for simple non-radioactive chemical reactions of first order.
Formula Used:
λ=2.303tlogN0N\lambda = \dfrac{{2.303}}{t}\log \dfrac{{{N_0}}}{N}
Here λ\lambda is the rate of decay
N0{N_0}is initial value of unstable nuclei
NN is the value of unstable nuclei after time tt
Also, for a first order reaction
λ=0.693t1/2\lambda = \dfrac{{0.693}}{{{t_{1/2}}}}
Here t1/2{t_{1/2}} is the time for the unstable nuclei to decay by 50%50\% of their initial value

Complete step by step solution:
Now for the given question t1/2{t_{1/2}} for iodide ion is given as eight days using that in the following formula we can calculate the decay for iodine ion as follow
λ=0.693t1/2\lambda = \dfrac{{0.693}}{{{t_{1/2}}}}
λ=0.6938\lambda = \dfrac{{0.693}}{8} (i)
Also
λ=2.303tlogN0N\lambda = \dfrac{{2.303}}{t}\log \dfrac{{{N_0}}}{N} (ii)
Here tt is given as 44 days
Equating both the equations (i) and (ii)
We get
0.6938=2.303tlogN0N\dfrac{{0.693}}{8} = \dfrac{{2.303}}{t}\log \dfrac{{{N_0}}}{N}
NN0=0.707\dfrac{N}{{{N_0}_{}}} = 0.707
This means that 70.7%70.7\% of the initial number of unstable nuclei are present.
While 66.67%66.67\% of the initial radioactivity was detected in the thyroid gland of the patient
Hence Weight of iodine migrated to the thyroid gland is 66.6770.7×0.1mg\dfrac{{66.67}}{{70.7}} \times 0.1\,mg
This comes out as 0.0958mg0.0958\,mg
Hence the option ‘A’ is the correct solution for the given question.

Note:
131I53^{131}{I_{53}} is an isotope of iodine that emits radiation. When a small dose of I131I - 131 is swallowed, it is absorbed into the bloodstream in the gastrointestinal (GI) tract and concentrated from the blood by the thyroid gland, where it begins destroying the gland's cells
Thyroid is a disease caused due to deficiency of iodine in the human body.