Question

A's age is $\frac{1}{6}$th of B's age. B's age will be twice of C's age after 10 years. If C's eighth birthday was celebrated two years ago, then the present age of A must be

• A. 5 years
• B. 10 years
• C. 15 years
• D. 20 years

Answer 1

Answer: (A)

5 years

Answer 2

The correct option is (A): 5 years
Let Age of B = $6x$ years, and age of A =$x$ years
and C' present age = 10 years
So, Acc. to ques:
⇒ $6x + 10 = 2 × (10 + 10)$
⇒$6x = 30$
⇒$x=5$
$\therefore$ Present age of A= 5 years.