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Question

Physics Question on mechanical properties of solids

A rubber cord of density d,d, Young?s modulus YY and length LL is suspended vertically. If the cord extends by a length 0.5L0.5\, L under its own weight, then LL is

A

Y2dg\frac{Y}{2dg}

B

Ydg\frac{Y}{dg}

C

2Ydg\frac{2Y}{dg}

D

dg2Y\frac{dg}{2Y}

Answer

Ydg\frac{Y}{dg}

Explanation

Solution

\because Young's modulus, Y= Stress  Strain Y=\frac{\text { Stress }}{\text { Strain }}
Y=(FA)(ΔLL)...(i)Y=\frac{\left(\frac{F}{A}\right)}{\left(\frac{\Delta L}{L}\right)}\,...(i)
\because Force exerted due to its own weight =mg2=\frac{m g}{2}
Y=(mg2)A(0.5L)=(mgAL)\therefore Y=\frac{\left(\frac{m g}{2}\right)}{A\left(\frac{0.5}{L}\right)}=\left(\frac{m g}{A L}\right)
So L=Y(mgAL)=Ydg(mAL=d)L=\frac{Y}{\left(\frac{m g}{A L}\right)}=\frac{Y}{d g}\left(\because \frac{m}{A L}=d\right)