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Physics Question on Inclined planes

A rough inclined plane BCEB C E of height (256)m\left(\frac{25}{6}\right)\, m is kept on a rectangular wooden block ABCDA B C D of height 10m10 m, as shown in the figure. A small block is allowed to slide down from the top EE of the inclined plane. The coefficient of kinetic friction between the block and the inclined plane is 18\frac{1}{8} and the angle of inclination of the inclined plane is sin1(0.6)\sin ^{-1}(0.6). If the small block finally reaches the ground at a point FF, then DFD F will be (Acceleration due to gravity, g=10ms2g =10 \,ms ^{-2} )

A

53m\frac{5}{3} m

B

103m\frac{10}{3} m

C

133m\frac{13}{3} m

D

203m\frac{20}{3} m

Answer

203m\frac{20}{3} m

Explanation

Solution

According to question, a small block is slide down from top EE of inclined plane as shown in figure,