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Question: A rope of length 5m is kept on frictionless surface and a force of 5N is applied to one of its end. ...

A rope of length 5m is kept on frictionless surface and a force of 5N is applied to one of its end. Find tension in the rope at 1m from this end

A

1 N

B

3 N

C

4 N

D

5 N

Answer

4 N

Explanation

Solution

T=F(Lx)L=5(51)5=4NT = \frac{F(L - x)}{L} = \frac{5(5 - 1)}{5} = 4N