Question

A rope brake is fitted to a flywheel of diameter = 1m. The flywheel runs at 220 r. p. m. It is required to absorb 5.25 kW of brake power. Difference in the two pulls (T - S) is

• A. 456 N
• B. 654 N
• C. 564 N
• D. 465 N

Answer 1

Answer: (A)

456 N

Answer 2

Here Brake power = $\frac { ( \mathrm { T } - \mathrm { S } ) ( 2 \pi \mathrm { R } ) \mathrm { N } } { 60,000 } \mathrm {~kW}$

or (T - S) = $\frac { 6000 \times \text { Brake power } } { 2 \pi \mathrm { RN } }$ = $\frac { 6000 \times 5.25 } { 2 \pi \times 0.5 \times 220 }$

= 455.8N ~ 456N