Question
Question: A roof has a cross-section as shown in the diagram. Find the height ‘h’ of the roof. 
Now, we can also find the area of the triangle XYZ by considering ‘XZ’ as the base and ‘YW’ as the height of the triangle. Therefore,
A=21×ZX×YW
Substituting, XZ = 10 m and YW = h, we get,
A=21×10×h⇒A=5h..................(ii)
Since, equation (i) and equation (ii) represent the area of the same triangle XYZ, therefore, the area given by these two equations must be equal.
Equating the areas given by equation (i) and equation (ii), we get,
24=5h⇒h=524⇒h=4.8 m
Hence, option (a) is the correct answer.
Note: One may note that we can also find the area of the triangle XYZ by using heron’s formula because all the three sides have been provided to us, but this will be a lengthy process. So, to solve this question in less time and to get rid of calculation, we have applied the formula: A=21×base×height. You may note that the areas are equated because we are finding the area of the same triangle two different times. Never use Pythagoras theorem in the triangles XYW or ZYW to solve this problem because we do not know the length of all the sides in these triangles.