Question

A rod of length 20 cm is rotating with angular speed of 100 rps in a magnetic field of strength 0.5 T about it’s one end. What is the potential difference between two ends of the rod

• A. 2.28 V
• B. 4.28 V
• C. 6.28 V
• D. 2.5 V

Answer 1

Answer: (C)

6.28 V

Answer 2

$e = \frac{1}{2}Bl^{2}\omega = Bl^{2}\pi\nu$

$\Rightarrow e = 0.5(20 \times 10^{- 2})^{2} \times 3.14 \times 100 = 6.28\mspace{6mu} V$