Question

A rod of length 2 m slides with a speed of 5 ms-1 on a rectangular conducting frame as shown in figure. There exists a uniform magnetic field of 0.04 T perpendicular to the plane of the figure. If the resistance of the rod is 3 Ω. The current through the rod is

• A. 75 mA
• B. 133 mA
• C. 0.75 A
• D. 1.33 A

Answer 1

Answer: (B)

133 mA

Answer 2

Current, $i = \frac{BIv}{R} = \frac{(0.04 \times 2 \times 5)}{3} = 133 \, \text{mA}$