Solveeit Logo

Question

Question: A rod of cross-sectional area \(10c{m^2}\) is placed with its length parallel to a magnetic field of...

A rod of cross-sectional area 10cm210c{m^2} is placed with its length parallel to a magnetic field of intensity103Am1{10^3}A{m^{ - 1}}, the flux through the rod is 104wb{10^4}wb. Then the permeability of material of the rod is:
(A) 104wb/Am{10^4}wb/Am
(B) 103wb/Am{10^3}wb/Am
(C) 102wb/Am{10^2}wb/Am
(D) 10wb/Am10wb/Am

Explanation

Solution

We are given here with the area of the cross section of the rod, the magnetic field intensity and the flux through the rod and are asked to find the permeability of material of the rod. Thus, we will use the formula of magnetic field which includes these parameters.

Formulae used:
ϕ=BA\phi = BA
Where, ϕ\phi is the magnetic flux through the material, BB is the magnetic field and AA is its cross-sectional area.
B=μHB = \mu H
Where, μ\mu is the permeability of the material and HH is the magnetic field intensity through the material.

Complete step by step solution:
Here,
We are given that,
ϕ=104wb\phi = {10^4}wb
H=103Am1H = {10^3}A{m^{ - 1}}
And
A=10cm2=10×104m2=103m2A = 10c{m^2} = 10 \times {10^{ - 4}}{m^2} = {10^{ - 3}}{m^2}
Now,
We know,
ϕ=BAB=ϕA\phi = BA \Rightarrow B = \dfrac{\phi }{A}
But,
B=μHB = \mu H
Thus, we can say
ϕA=μH\dfrac{\phi }{A} = \mu H
After further rearrangements, we get
μ=ϕAH\mu = \dfrac{\phi }{{AH}}
Putting in the values
μ=104103×103wb/Am\mu = \dfrac{{{{10}^4}}}{{{{10}^{ - 3}} \times {{10}^3}}}wb/Am
After calculations, we get
μ=104wb/Am\mu = {10^4}wb/Am

Hence, the correct answer is (A).

Additional Information
The physical significance of permeability is the extent to which a material can enhance a magnetic field passing through it. It is the qualitative measure of the ability of a material to enhance a magnetic field. On the basis of this parameter, materials can be further classified into three types:
1. Paramagnetic: Has a constant relative permeability slightly greater than11.
2. Diamagnetic: Has a constant relative permeability slightly lower than11.
3. Ferromagnetic: Does not have a constant relative permeability.

Note: We got the answer to be a very high value, thus the material cannot be classified into neither paramagnetic nor a diamagnetic. It could possibly be a ferromagnetic material.