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Question

Physics Question on Waves

A rocket is moving at a speed of 200m/s200 \,m/s towards a stationary target. While moving it emits a wave of frequency 1000Hz1000 \,Hz . Some of the sound reaching the target gets reflected back to the rocket as an echo. The frequency of the echo as detected by the rocket is (velocity of sound =330m/s= 330 \,m/s )

A

1000Hz1000\, Hz

B

1580Hz1580\, Hz

C

2540Hz2540\, Hz

D

4080Hz4080\, Hz

Answer

4080Hz4080\, Hz

Explanation

Solution

Given, speed of rocket, v1=200m/sv_{1}=200 \, m/s
Frequency emitted by the rocket, v1=1000HZv_{1}=1000\,HZ
Velocity of sound, vsound=330m/sv_{sound}=330\, m/s

Apply Doppler's effect in sound's equation
v=v+u0vu1v=\frac{v+u_{0}}{v-u_{1}}
Putting values,
v1=330+0330220×1000v_{1}=\frac{330+0}{330-220} \times 1000
v1=3313×1000Hz(i)v_{1}=\frac{33}{13} \times 1000\,Hz \dots(i)
This frequency is reflected back to the rocket

Apply Doppler's effect in sound's equation
v2=330+200300v1v_{2}=\frac{330+200}{300}v_{1}
=530330×3313×1000=\frac{530}{330}\times \frac{33}{13}\times 1000 [from E (i)]
=5313×1000=4076.92Hz=\frac{53}{13}\times1000=4076.92\,Hz
Thus, the most appropriate option is (d)