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Question: A rigid circular loop of radius r and mass m lies in the x-y plane of a flat table and has a current...

A rigid circular loop of radius r and mass m lies in the x-y plane of a flat table and has a current flowing in it. At this particular place the earth's magnetic field is = Bx + Bz. The value of i so that the loop start tilting is-

A

B

mgπrB\frac { \mathrm { mg } } { \pi \mathrm { rB } }

C

D

mgπrBxBz\frac { \mathrm { mg } } { \pi \mathrm { r } \sqrt { \mathrm { B } _ { \mathrm { x } } \mathrm { B } _ { \mathrm { z } } } }

Answer

mgπrB\frac { \mathrm { mg } } { \pi \mathrm { rB } }

Explanation

Solution

M\overrightarrow { \mathrm { M } } = i(πr2), B\vec { B } = Bx i + Bz

for start tilting τdue to mass

= τmagnetic (mg)r| ( \mathrm { mg } ) \mathrm { r } | = M×B| \overrightarrow { \mathrm { M } } \times \overrightarrow { \mathrm { B } } | (mg) (r) = i(πr2)(Bx) i =