Question
Question: A resistor of resistance 100ohm is connected to an AC source \[E=12\sin 250\pi {{s}^{-1}}\]. Find th...
A resistor of resistance 100ohm is connected to an AC source E=12sin250πs−1. Find the energy dissipated as heat during t=0 to t=1.0ms
Explanation
Solution
In this problem, we are given AC, so to find out the value of heat we will have to integrate the heat formula over the given value of time. The time is given in millisecond and you have to convert it into seconds
Complete step by step answer:
Given values, E= 12 V
Resistance = 100 Ω
We need to find the energy dissipated for the given time.
Time is 0 to 1 ms that is 10−3s
Using the formula, H=0∫10−3RE2dt
We are given that E=12sin250πs−1 comparing this with the standard equation we get,
ω=250πs−1
So, H=0∫10−3RE2dt