Question

A resistor of 500$\sqrt { 2 }$sin(1000t).

• A. $\frac { 1 } { \sqrt { 2 } }$
• B. $\frac { 1 } { \sqrt { 3 } }$
• C. 0.5
• D. 0.6

Answer 1

Answer: (A)

$\frac { 1 } { \sqrt { 2 } }$

Answer 2

: Here,

Compare V = 100$\sqrt { 2 }$sin (1000t) with V =

we get , $\omega = 1000$

the inductive reactance is

$X _ { L } = \omega L = ( 1000 ) ( 0.5 ) = 500 \Omega$

Impedance of the RL circuit is

Power factor,

$\cos \phi = \frac { R } { Z } = \frac { 500 \Omega } { 500 \sqrt { 2 } \Omega } = \frac { 1 } { \sqrt { 2 } }$