Question
Physics Question on Alternating current
A resistance wire of 72Ω is connected across 120 V dc source. When a similar wire is connected in paralllel with the first wire, change in power dissipated is
A
400Ω
B
200Ω
C
800Ω
D
100Ω
Answer
200Ω
Explanation
Solution
Using, P = RV2 we have P' = R/2V2=72120×120 = 40 W and
P = RV2=72120×120 = 200 W
Thus, ΔP = 400 - 200 = 200 W