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Question

Physics Question on Alternating current

A resistance wire of 72Ω72\,\Omega is connected across 120 V dc source. When a similar wire is connected in paralllel with the first wire, change in power dissipated is

A

400Ω400\,\Omega

B

200Ω200\,\Omega

C

800Ω800\,\Omega

D

100Ω100\,\Omega

Answer

200Ω200\,\Omega

Explanation

Solution

Using, P = V2R\frac{V^2}{R} we have P' = V2R/2=120×12072\frac{V^2}{R/2} = \frac{120 \times 120}{72} = 40 W and
P = V2R=120×12072\frac{V^2}{R} = \frac{120 \times 120}{72} = 200 W
Thus, Δ\DeltaP = 400 - 200 = 200 W