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Question: A resistance of 20 ohm is connected to a source of an alternating potential V = 220 sin (100pt). The...

A resistance of 20 ohm is connected to a source of an alternating potential V = 220 sin (100pt). The time taken by the current to change from its peak value to rms value is-

A

0.2 sec

B

0.25 sec

C

25 × 10–3sec

D

2.5 × 10–3sec

Answer

2.5 × 10–3sec

Explanation

Solution

V02\frac{V_{0}}{\sqrt{2}} = V0 sin(wt)

2πT\frac{2\pi}{T} × t = π4\frac{\pi}{4} Ž t1 = 78\frac{7}{8}

Time taken to reach the peak is T4\frac{T}{4}

\ interval = T4T8\frac{T}{4} - \frac{T}{8} = T8\frac{T}{8} = 18f=18×50\frac{1}{8f} = \frac{1}{8 \times 50}

= 1400\frac{1}{400} = 2.5 × 10–3 sec.