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Question

Physics Question on Current electricity

A resistance of 2Ω2 \Omega is connected across one gap of a meter-bridge (the length of the wire is 100cm100\, cm) and an unknown resistance, greater than 2Ω2 \Omega, is connected across the other gap. When these resistances are interchanged, the balance point shifts by 20cm20\, cm. Neglecting any corrections, the unknown resistance is

A

3Ω3 \Omega

B

4Ω4 \Omega

C

5Ω5 \Omega

D

6Ω6 \Omega

Answer

3Ω3 \Omega

Explanation

Solution

R>2Ω100x>xR > 2 \Omega \Rightarrow \, \, \therefore \, \, \, 100-x > x
ApplyingPQ=RSApplying \, \, \, \, \, \, \, \, \, \frac{P}{Q} = \frac{R}{S}
Wehave2R=x100x...(i)We \, have \, \, \, \, \, \, \, \, \, \, \frac{2}{R} = \frac{x}{100 - x} \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, ...(i)
R2=x+2080x...(ii)\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \frac{R}{2} = \frac{x + 20}{80 - x} \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, ...(ii)
SolvingEqs.(i)and(ii),weget,R=3ΩSolving \, Eqs. \, (i) \, and \, (ii),\, we \, get, \, R = 3 \Omega
\therefore Correct option is (a).