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Question: A rectangular slab of refractive index μ is placed over another slab of refractive index 3, both sla...

A rectangular slab of refractive index μ is placed over another slab of refractive index 3, both slabs being identical in dimensions. If a coin is placed below the lower slab, for what value of μwill the coin appear to be placed at the interface between the slabs when viewed from the top

A

1.8

B

2

C

1.5

D

2.5

Answer

1.5

Explanation

Solution

Apparent depth of coin as seen from top =xμ1+xμ2=x= \frac { x } { \mu _ { 1 } } + \frac { x } { \mu _ { 2 } } = x

1μ1+1μ2=1\Rightarrow \frac { 1 } { \mu _ { 1 } } + \frac { 1 } { \mu _ { 2 } } = 1 13+1μ=1\Rightarrow \frac { 1 } { 3 } + \frac { 1 } { \mu } = 1

μ=1.5\Rightarrow \mu = 1.5