Question

A rectangular loop of sides 6 cm and 2 cm with a small cut is moving out of a region of uniform magnetic field of magnitude 0.4 T directed normal to the loop. The voltage developed across the cut if velocity of loop is 2 cm s-1 in a direction normal to the longer side is

• A. 3.8 × 10-4 V
• B. 4.8 × 10-4 V
• C. 2.2 × 10-2 V
• D. 3.2 × 10-2 V

Answer 1

Answer: (B)

4.8 × 10-4 V

Answer 2

Here , $l = 6cm = 6 \times 10^{- 2}$

$B = 0.4T$

$v = 2cms^{- 1}$

$= 2 \times 10^{- 2}ms^{- 1}$

Voltage developed is

$\varepsilon = Blv = 0.4 \times 6 \times 10^{- 2} \times 2 \times 10^{- 2}$

$= 4.8 \times 10^{- 4}V$