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Question

Physics Question on Electromagnetic induction

A rectangular coil of 100100 turns and size 0.1×0.05m0.1 \times 0.05\, m is placed perpendicular to a magnetic field of 0.1T0.1\, T. The induced emf when the field drops to 0.05T0.05\, T in 0.05s0.05\, s is

A

0.5 V

B

1.0 V

C

1.5 V

D

2.0 V

Answer

0.5 V

Explanation

Solution

The induced emf
e=NΔϕΔte=-N \frac{\Delta \phi}{\Delta t}
or e=N(B2B1)AΔte=-\frac{N\left(B_{2}-B_{1}\right) A}{\Delta t}
or e=100(0.10.05)×0.1×0.050.05e =-\frac{100(0.1-0.05) \times 0.1 \times 0.05}{0.05}
e=0.5Ve =0.5\, V