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Question: A rectangular block is heated from 0<sup>0</sup>C to 100<sup>0</sup>C. The percentage increase in it...

A rectangular block is heated from 00C to 1000C. The percentage increase in its length is 0.10%. What will be the percentage increase in its volume ?

A

(a) 0.03 %

A

(b) 0.10 %

A

(c) 0.30 %

A

(d) None

Explanation

Solution

(c)

a = 10–5/ŗC Δll\frac{\Delta\mathcal{l}}{\mathcal{l}} = 0.10%, DT = 100ŗC

\ Δll\frac{\Delta\mathcal{l}}{\mathcal{l}} = a Dq and ΔVV\frac{\Delta V}{V} = g. Dq = 3a.Dq