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Question: A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.2%. The ...

A rectangular block is heated from 0°C to 100°C. The percentage increase in its length is 0.2%. The percentage increase in its volume is

A

0.6%

B

0.10%

C

0.2%

D

0.4%

Answer

0.6%

Explanation

Solution

Volume V=L3V = L^{3}

ΔVV×100=3ΔLL×100=3×0.2%=0.6%\therefore\frac{\Delta V}{V} \times 100 = 3\frac{\Delta L}{L} \times 100 = 3 \times 0.2\% = 0.6\%

(ΔLL=0.2%)\left( \because\frac{\Delta L}{L} = 0.2\% \right)