Question

A reaction, which is second order, has a rate constant of 0.002 L mol–1 s–1. If the initial conc. of the reactant is 0.2 M. how long will it take for the concentration to become 0.0400 M?

• A. 1000 s
• B. 400 s
• C. 200 s
• D. 10, 000 s

Answer 1

Answer: (D)

10, 000 s

Answer 2

$\frac{1}{Ct} = \frac{1}{C_{0}} = + Kt.$

}{\Rightarrow t = \frac{20}{2 \times 10^{- 3}} = 10,000sec,}$$