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Question

Chemistry Question on Thermodynamics

A reaction occurs spontaneously if :

A

TΔS<ΔH{ T \Delta S < \Delta H } and both ΔH\Delta H and ΔS\Delta S are +ve

B

TΔS>ΔH{ T \Delta S > \Delta H } and both ΔH\Delta H and ΔS\Delta S are +ve

C

TΔS=ΔH{ T \Delta S = \Delta H } and both ΔH\Delta H and ΔS\Delta S are +ve

D

TΔS>ΔH{ T \Delta S > \Delta H } and ΔH\Delta H is + ve and ΔS\Delta S is -ve

Answer

TΔS>ΔH{ T \Delta S > \Delta H } and both ΔH\Delta H and ΔS\Delta S are +ve

Explanation

Solution

The spontaneity of reaction is based upon the negative value of ΔG,ΔG\Delta G,\,\,\Delta G is based upon T,ΔST,\,\,\Delta S and ΔH\Delta H according to following equation.
(Gibbs-Helmholtz equation)
ΔG=ΔHTΔS\Delta G=\Delta H-T\Delta S
If the magnitude of ΔHTΔS\Delta H-T\Delta S is negative, then the reaction is spontaneous, when TΔS>ΔHT\Delta S>\Delta H and ΔH\Delta H and ΔS\Delta S are +ve, then ΔG\Delta G is negative.