Question

A reaction is at equilibrium at $100^{o}C$ and the enthalpy change for the reaction is $42.6kJmol^{- 1}$ What will be the value of $\Delta SinJK^{- 1}mol^{- 1?}$

• A. 120
• B. $426.2$
• C. $373.1$
• D. $114.2$

Answer 1

Answer: (D)

$114.2$

Answer 2

: $\Delta G = \Delta H - T\Delta S$

At equilibrium, $\Delta G = 0,\Delta H = T\Delta S$

$\Delta S = \frac{\Delta H}{T} = \frac{42600Jmol^{- 1}}{373K} = 114.2JK^{- 1}mol^{- 1}$