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Question: A reaction has \(\Delta\)H = – 33 kJ and \(\Delta\)S = – 58\(\frac{J}{K}\). This reaction would be :...

A reaction has Δ\DeltaH = – 33 kJ and Δ\DeltaS = – 58JK\frac{J}{K}. This reaction would be :

A

Spontaneous at all temperatures

B

Non-spontaneous at all temperatures

C

Spontaneous above a certain temperature

D

Spontaneous below a certain temperature

Answer

Spontaneous below a certain temperature

Explanation

Solution

Δ\DeltaG = (Δ\DeltaH) – T(Δ\DeltaS)

\downarrow \downarrow

–ve –ve

since both are –ve, the reaction would have a –ve Δ\DeltaG below a temperature of 3300058\frac{33000}{58} K ( = 569K)