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Question

Chemistry Question on Chemical Kinetics

A reactant (A) forms two products : A>[k1]B,{A ->[k_1] B,} Activation Energy Ea1Ea_1 A>[k2]C, {A ->[k_2] C,} Activation Energy Ea2Ea_2 If Ea2=2Ea1Ea_2 = 2 Ea_1, then k1k_1 and k2k_2 are related as :

A

k2=k1eEa1/RTk_{2} = k_{1}e^{Ea_{1} /RT}

B

k2=k1eEa2/RTk_{2} = k_{1}e^{Ea_{2} /RT}

C

k1=Ak2eEa1/RTk_{1} = Ak_{2}e^{Ea_{1} /RT}

D

k1=2k2eEa2/RTk_{1} = 2k_{2}e^{Ea_{2} /RT}

Answer

k1=Ak2eEa1/RTk_{1} = Ak_{2}e^{Ea_{1} /RT}

Explanation

Solution

k1=A1eEa1/RTk_{1} = A_{1} e^{-Ea_{1} /RT} k2=A2eEa2/RTk_{2} = A_{2} e^{-Ea_{2} /RT} k1k2=A1A2e(Ea2Ea1)/RT\frac{k_{1}}{k_{2}} = \frac{A_{1}}{A_{2}}e^{\left(E_{a_2}- E_{a_1} \right) /RT} k1=A1×eEa1/RTk_{1} = A_{1} \times e^{Ea_{1} /RT}