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Question: A ray of light when incident upon a prism suffers a minimum deviation of 39<sup>0</sup>. If the shad...

A ray of light when incident upon a prism suffers a minimum deviation of 390. If the shaded half portion of the prism is removed, then the same ray will -

A

Suffer a deviation of 19.50

B

Suffer a deviation of 390

C

Not suffer any deviation

D

Will be totally internally reflected

Answer

Suffer a deviation of 19.50

Explanation

Solution

d = (µ – 1) A

d µ A

\ δ2δ1=A2 A1\frac { \delta _ { 2 } } { \delta _ { 1 } } = \frac { \mathrm { A } _ { 2 } } { \mathrm {~A} _ { 1 } }

\ δ2δ1=A/2 A\frac { \delta _ { 2 } } { \delta _ { 1 } } = \frac { \mathrm { A } / 2 } { \mathrm {~A} }= 12\frac { 1 } { 2 }

\ d2 = δ12\frac { \delta _ { 1 } } { 2 }

d2 = 392\frac { 39 } { 2 }= 19.50