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Question

Physics Question on Ray optics and optical instruments

A ray of light travelling in the direction 12(i^+3)\frac{1}{2}(\hat{i}+\sqrt{3}) is incident on a plane mirror. After reflection, it travels along the direction 12(i^3j)\frac{1}{2}(\hat{i}-\sqrt{3} j). The angle of incidence is

A

3030^{\circ}

B

4545^{\circ}

C

6060^{\circ}

D

7575^{\circ}

Answer

3030^{\circ}

Explanation

Solution

Let angle between the directions of incident ray and reflected ray be θ\theta
cosθ=12(i^+3j^)12(i^3j^)\cos \theta=\frac{1}{2}(\hat{i}+\sqrt{3} \hat{j}) \cdot \frac{1}{2}(\hat{i}-\sqrt{3} \hat{j})
cosθ=12\cos \theta=-\frac{1}{2}
θ=120\theta=120^{\circ}