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Question

Physics Question on Refraction of Light

A ray of light passes through four transparent media with refractive indices μ1,μ2,μ3\mu_1,\mu_2,\mu_3 and μ4\mu_4 as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

A

μ1=μ2\mu_1=\mu_2

B

μ2=μ3\mu_2=\mu_3

C

μ3=μ4\mu_3=\mu_4

D

μ4=μ1\mu_4=\mu_1

Answer

μ4=μ1\mu_4=\mu_1

Explanation

Solution

Applying Snell's law at B and C,
μ\mu sin i=costant or
μ1siniB=μ4dinic\mu_1 sin i_B=\mu_4 din i_c
But \hspace15mm AB||CD
\therefore \hspace15mm i_B=i_C
or \hspace15mm \mu_1=mu_4
NOTE The Snell's law, which the
students read in their plus two syllabusμ=sinisinr\mu=\frac{sin i}{sin r} is derived from
μ\mu sin i= constant
or \hspace25mm \mu_1sin i_1=\mu_2 sin i_2
Here: μ1=1,μ2=μ,\mu_1=1,\mu_2=\mu,
or sin i=μ\mu sin r or μ=sinisinr\mu=\frac{sin i}{sin r}